(2x+1)^2=3x^2+6

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Solution for (2x+1)^2=3x^2+6 equation: 



(2x+1)^2=3x^2+6

We move all terms to the left:

(2x+1)^2-(3x^2+6)=0

We get rid of parentheses

-3x^2+(2x+1)^2-6=0

We move all terms containing x to the left, all other terms to the right

-3x^2+(2x+1)^2=6

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